k^2=25/36

Solution for k^2=25/36 equation:

k^2=25/36

We move all terms to the left:

k^2-(25/36)=0

We add all the numbers together, and all the variables

k^2-(+25/36)=0

We get rid of parentheses

k^2-25/36=0

We multiply all the terms by the denominator


k^2*36-25=0

Wy multiply elements

36k^2-25=0

a = 36; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·36·(-25)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*36}=\frac{-60}{72}
=-5/6
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*36}=\frac{60}{72}
=5/6
$